A.y1<y2<0 B.y1>y2>0 C.y2<y1<0 D.y2>y1>0

试题分析:根据题意得2y1=k,3y2=k,即y1=k/2, y2=k/3,
∵k<0,
∴y1<y2<0.
故选A.